11/29/2022 0 Comments Rules of the game of life![]() | That the bitwise OR of the result and G. This zips back and adds the surrounding columns to each column.Įach cell now contains the number of lit cells that surround it. Μ Convert the preceding chain into a link and begin a new chain. S Compute the sum of the three resulting grids.Įssentially, this adds the rows directly above and below each given Ṛ Rotate the rows of G -1, 0 and 1 units up. ¤ Evaluate the three links to the left as a niladic chain. Larger test cases (from answer): 15×15 stable | 15×14 glider How it works ṙ-r1¤SZµ⁺_|=3 Helper link. Only on older perl versions (where you could use a constant as a variable) does this 126 byte solution work: #!/usr/bin/perl case there are certain to be at least 2 rows this 123 byte solution works on all perl versions: #!/usr/bin/perl 26 25 bytes ṙ-r1¤SZµ⁺_|=3 : #!/usr/bin/perl beating Mathematica on this one. Giving input this way would however give 1 instead of 0 for an immediately stable configuration. With each subsequent playing getting a little less in bonus pay. It is now simply that the first person to reach the end gets the biggest cash bonus. In all other cases you can also more conveniently give it as seperate lines of digits: Also at the ending, you no longer have to guess if you should go to the Millionaire Mansion or not and pray that you have the most money otherwise you lose the game. This is only really needed in case the input is immediately stable. Run with the input as a line of groups of digits separated by space <<< "0000 0001 0111 0010" Let's go through the code: computes 2 N, since is used to flatten a 2D list. Afterwards, we find the first pair of consecutive identical states in the simulated history. This guarantees that if the system settles into a stable state, we've reached it. This simply simulates the Game of Life for 2 N steps where N is the number of cells in the input. Mathematica, 130 129 bytes wouldn't recommend trying more than 4x4 inputs, because it's going to take forever (and a lot of memory). If a cell that is on is next to 2 or 3 on squares, it says on. RULES OF THE GAME OF LIFE HOW TOIf a cell that is off (0) is next to exactly three on (1) cells, it is turned on. Simply I give you the RULES to play the GAME to the best of your abilities Money How to become financially independent and the owner of your time. Process: (this does not need to be displayed) , Note: If the matrix starts in a stable state, the output should be 0. given a 4x3 matrix it should run on a 4x3 torus) The input matrix will not be larger than 15x15. The game must run in the given matrix, with the top and bottom connected, and the sides connected. A stable state is a state in which no cells are turned on or off each step. Given a matrix (or 2d array) of 0s and 1s, output the number of steps it takes for Conway's game of life to reach a stable state, or -1 if it never reaches one. ![]()
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